SOLUTION: Solve the quadratic equation by using the quadratic formula. This is what I get: 2x^2+4x=-1 2x^+4x+1=0 x=[-(4)+or- sqrt(4)^2-4(2)(1)]/[2(2)] x=[-4+or-sqrt16-8]/4 x=

Algebra ->  Algebra  -> Quadratic Equations and Parabolas  -> Quadratic Equations Lessons  -> Quadratic Equation Lesson -> SOLUTION: Solve the quadratic equation by using the quadratic formula. This is what I get: 2x^2+4x=-1 2x^+4x+1=0 x=[-(4)+or- sqrt(4)^2-4(2)(1)]/[2(2)] x=[-4+or-sqrt16-8]/4 x=      Log On

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Question 30765: Solve the quadratic equation by using the quadratic formula.
This is what I get:
2x^2+4x=-1
2x^+4x+1=0
x=[-(4)+or- sqrt(4)^2-4(2)(1)]/[2(2)]
x=[-4+or-sqrt16-8]/4
x=[-4+or-sqrt8]/4
my answer x=[-4+or-2sqt2]/4
my bookk says its:
x=[-2+or-sqrt2]/2
How do they get there?
Answer by mbarugel(146) About Me  (Show Source):
You can put this solution on YOUR website!
You actually got the correct solution, and it's the same as the book's.
You have:
%28-4%2B2sqrt%282%29%29%2F4
But you can divide both the numerator and the denominator by 2:
%28-4%2F2+%2B+2%2F2sqrt%282%29%29%2F%284%2F2%29+=+%28-2+%2B+sqrt%282%29%29%2F2
which is the solution your book gives. You had found the correct answer :)
I hope this helps!
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