Tutors Answer Your Questions about Quadratic Equations (FREE)
Question 33519: Quadrilateral- find the value of x. I have tried and tried to work this out and when I plug in my answer it doesnt figure. Please help I would appreciate it.
(x+30)+(x-55)+(x-45)+ x=360 Thank you so very much!!
Click here to see answer by Cintchr(481) |
Question 33583: Use the square root property to solve the equation, show steps and explain
x^2=36
(x^2-36)=0 Factor out the left-side
(x-6) (x+6)=0 (? lost after this point)
(x-6)=0 or (x+6)=0
Thank you
Click here to see answer by priya(51) |
Question 33585: Please check my work, am I doing this correctly?
Solve using the square root property:
x+8)^2=81
Þ ((x+8)2-81) = 0
Þ (x2+16x-17) = 0
Þ (x2-x+17x-17) = 0
Þ x(x-1)+17(x-1) = 0
Þ (x+17)(x-1) = 0
Þ (x+17) = 0 OR (x-1) = 0
Þ x = -17 OR x = 1
Click here to see answer by priya(51) |
Question 33634: Please check my work
Solve using the quadratic equation:
(3x^2-2x) + (-15x+10)=0
(3x^2 - 17x +10)= 0
(3x^2 -2x -15x +10)=0
x(3x-2) + (-5) (3x-2)=0
(x-5)(3x-2)=0
(x-5)=0 or (3x-2)=0
x=5 or 3x=2
x=5 or x=2/3
Click here to see answer by sarah_adam(201) |
Question 33247: A toy rocket is launched from a point 60m from a school building. The school building is 40m wide. On the other side of the building is a 15m wide parking lot and next to it is a pond that is 10m wide. The rocket is aimed over the building to land in the center of the pond, 120m away. The building is 30m tall. The rocket's trajectory should be as low as possible and the rocket should clear the building by at least 5m. What is the equation for the parabola formed by the trajectory. Graph the parabola.
Click here to see answer by Fermat(127)  |
Question 33681: A retailer spent $48 to purchase a number of special mugs. Two of them were broken i the store, but by selling each of the remaining mugs for $3 above the original cost per mug, she made a total profit of $22. Construct an equation that will allow us solve for the number of mugs, denoted by n, that were originally purchased. If the price for n mugs is $48, how can we express the cost per mug?
Click here to see answer by Paul(988) |
Question 33685: I don't know how to solve x(to the fourth) minus (five x squared) plus four.
In school we did something called a diamond formula or something with a diamond and it makes everything easier but i don't understand. Can you explain to me how to solve this by the diamond formula. Thank you.
Click here to see answer by Earlsdon(6294) |
Question 33706: If we apply the quadratic formula and find that the value of b2 - 4ac equals zero, what can we conclude about the solutions?
A) The equation has no real number solutions.
B) The equation has exactly one irrational solution.
C) The equation has two different rational solutions
D) The equation has exactly one rational solution.
Click here to see answer by ntnk(54) |
Question 33706: If we apply the quadratic formula and find that the value of b2 - 4ac equals zero, what can we conclude about the solutions?
A) The equation has no real number solutions.
B) The equation has exactly one irrational solution.
C) The equation has two different rational solutions
D) The equation has exactly one rational solution.
Click here to see answer by Nate(3500) |
Question 33706: If we apply the quadratic formula and find that the value of b2 - 4ac equals zero, what can we conclude about the solutions?
A) The equation has no real number solutions.
B) The equation has exactly one irrational solution.
C) The equation has two different rational solutions
D) The equation has exactly one rational solution.
Click here to see answer by ice_water35(8) |
Question 33709: 6) If we apply the quadratic formula and find that the value of b^2 - 4ac equals zero, what can we conclude about the solutions?
A) The equation has no real number solutions.
B) The equation has exactly one irrational solution.
C) The equation has two different rational solutions
D) The equation has exactly one rational solution.
Click here to see answer by venugopalramana(3286) |
Question 34173: I need help with the following 2 questions...
1. Solve by extracing square roots: 3x^2-80=0
I figured this was it, can you check the work?
3x^2 - 80 = 0
3x^2 = 80
3x^2/3 = 80/3
x^2 = 80/3
sq root of x^2 = sq root of 80/3
Answer - x=sq root of (= or -)80/3?? Does the (+ or -) have to be there?
2. Solve by extracting square roots: (2x-2)^2 = 9
sq root of (2x-2)^2 = sq root of 9
2x-2 = (+ or -)3
This is where I am confused... is the next step dividing it all by 2, or taking the -2 to the other side of the problem? Could you please help me get though this one?
Thanks!
Click here to see answer by Cintchr(481) |
Question 34172: I need help with the following 2 questions...
1. Solve by extracing square roots: 3x^2-80=0
I figured this was it, can you check the work?
3x^2 - 80 = 0
3x^2 = 80
3x^2/3 = 80/3
x^2 = 80/3
sq root of x^2 = sq root of 80/3
Answer - x=sq root of (= or -)80/3?? Does the (+ or -) have to be there?
2. Solve by extracting square roots: (2x-2)^2 = 9
sq root of (2x-2)^2 = sq root of 9
2x-2 = (+ or -)3
This is where I am confused... is the next step dividing it all by 2, or taking the -2 to the other side of the problem? Could you please help me get though this one?
Click here to see answer by Cintchr(481) |
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