Question 539715: I need help solving a quadratic equation.
The area of a field shaped like a right triangle is 600m2 ( squared). The legs of the field are fenced with steel at $10/m, while the hypotenuse is fenced with aluminum at $20/m. The perimeter of the field is 120m. The total cost of the fencing is $1700.
A. What is the length of each side of fence with steel?
B. what is the length of the side of the fence with aluminum?
Here's what I've tried:
10x + 10y + 20z = $1700 or x+ y + 2z = $170
Not sure how to get rid of one of the variables.
Would greatly appreciate your assistance.
Daniel Answer by mananth(12270) (Show Source):
x+ y + 2z = $170
y= 40 OR 30
The sides of triangle are 40,30,50
50 is the hypotenuse
Area = 1/2 * 30*40= 600 (check)
Now you know how to answer the questions