SOLUTION: The value of a share of a company can be represented by V(x) = x2 – 6x + 13, where x is the number of months after January 2004. What is the lowest value V(x) will reach, and when

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equations Lessons -> SOLUTION: The value of a share of a company can be represented by V(x) = x2 – 6x + 13, where x is the number of months after January 2004. What is the lowest value V(x) will reach, and when      Log On


   



Question 224404: The value of a share of a company can be represented by V(x) = x2 – 6x + 13, where x is the number of months after January 2004. What is the lowest value V(x) will reach, and when did that occur?
Answer by stanbon(75887) About Me  (Show Source):
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The value of a share of a company can be represented by V(x) = x2 – 6x + 13, where x is the number of months after January 2004. What is the lowest value V(x) will reach, and when did that occur?
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V is a quadratic with a=1,b=-6,c = 13
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Mimum V occurs at x = -b/2a = 6/2 = 3
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The minimum V value = V(3) = 3^2-6*3+13 = 16
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Cheers,
Stan H.