You can
put this solution on YOUR website!The total area including the frames border is 34*17 or 578 cm^2
The area of the border alone is 578-318=260 cm^2
If you draw a picture, you may be able to follow what I'm doing
Area of the border=2(34*x)+2x(17-2x) and this equals
68x+34x -4x^2and we know that this equals 260 cm^2
-4x^2+102x-260=0 divide each term by -2
2x^2-51x+130=0-------------------quadratic in standard form
Another way to arrive at this quadratic is to realize that the length and width of the picture that's showing is (34-2x) and (17-2x) and we know that
(34-2x)(17-2x)=318 expanding, using FOIL, we get:
578-68x-34x+4x^2=318 subtract 318 from each side
578-318-102x+4x^2=318-318 collecting like terms
260-102x+4x^2=0 divide each term by 2
2x^2-51x+130=0-----------quadratic in standard
Can you solve using the quadratic formula?
cm DOESN'T WORK---LEADS TO NEGATIVE VALUE FOR AREA
and
cm
CK
(34-2x)(17-2x)=318
34-2*2.872)(17-2*2.872)=318
28.255*11.256=318
~~~~~~318=318
Hope this helps--ptaylor
