Question 12636: Hi all,
One more question and I should be about done with algebra for awhile. The directions here say to solve for the roots.
I have no clue how to do this.
Thanks for the help Answer by AdolphousC(70) (Show Source):
You can put this solution on YOUR website! You need to get Zero on the right side of the equation by subtracting 6p and 5 from both sides of your equation, this leaves you with...
Now you need to find the roots,
Step 1: Multiply the P^2 Coefficient with your constant ( 1 * 20 ) = 20
Step 2: List the factors of 20
Step 3: Out of the factors, are there any that when you add them together give you your P term, in this case 9.
Yes ( 5 + 4 = 9 )
Step 4: Split the middle term into its two factors
Step 5: Group
Step 6: Take out GCF From each group
Step 7: You need two sets of '()' one set is the one term inside '()' the other set is what is left over ( technically factoring out a (P+5) )
Step 8: FOIL to Check
Step 9: the ROOTS of a Quadratic are where the Quadratic crosses the X-Axis, and where the function evaluates to Zero.
In order for to be true either
P + 5 = 0 There for P = -5 OR
P + 4 = 0 There for P = -4
So, -5 and -4 are your roots