Tutors Answer Your Questions about Quadratic Equations (FREE)
Question 32509: Three peices of string measure 20 cm, 41 cm and 44 cm. if the same amount is cut off all three peices, the remaining peices can be formed into a right-angled triangle. What length should be cut from each peice of string?
Click here to see answer by stanbon(57361)  |
Question 32563: A company determines that the cost C, in dollars of producing x tennis rackets is C= 32x+120,000. the revenue R in dollars, from selling all of the tennis racquets is R = x(200-0.01x).
How many rackets should the company manufacture and sell if the company wishes to earn a profit of at least $550.000?
Solution:
-0.01x^2+168x-670,000is >or= to 0
It says use the quadratic formula to find the approximate values of the inequality, but I keep coming up with a -under the radical sign and can't solve it. Can someone write out what I am doing wrong w/ finding the approximate values? The approximate critical values are supposed to be 6513.2 and 10,286.8, so the company should manufacture at least 6514 racquets but not more than 10,286 to produce the desired proffit. I am lost on how they are getting this answer.
Click here to see answer by stanbon(57361) |
Question 32495: The Empire State Bldg is 1250 ft tall. If an object thrown upward from the top of the building at an initial velocity of 35 ft per second, its height after "t" seconds after it is thrown is given by the
function h(t)= -16t^2+35t+1250. How long will it be before the oject hits the ground?
Click here to see answer by Fermat(127)  |
Question 32754: How would you solve the following using the quadratic formula - showing step by step? I know the book says the answer is 2 +- sqrt(2) /2.
However, I can't seem to come up with that. Here is the problem:
(3y-1)(2y-3)=y
Here's what I have so far:
= -(-12) +- sqrt((-12)^2 -4(6)(3) / 2(6)
= 12 +- sqrt(144-72) / 12
= 12 +- sqrt(72) / 12
= 12+- sqrt(36 *2) / 12
= 12 +- 6 sqrt(2) / 12
then what would follow? Thank you.
Click here to see answer by mukhopadhyay(490) |
Question 32740: Please ;') A right triangle is a triangle with one angle measuring 90°. In a right triangle, the sides are related by Pythagorean Theorem, where c is the hypotenuse (the side opposite the 90° angle). Find the hypotenuse when the other 2 sides’ measurements are 3 feet and 4 feet.
Click here to see answer by sarah_adam(201) |
Question 32675: This is my question:express each of the following in the form y = a(x - h)^2 + k.
Hence state the coordinate of the turning point and sketch the graph in each case:
a)x^2 - 2x + 3
b)x^2 - 8x +12
c)- x^2 + 4x + 1
d)x^2 +4x + 1
Can you show me the solution of these exercise.
Click here to see answer by kietra(57) |
Question 31905: When using the quadratic formula to solve a quadratic equation (ax2 + bx + c = 0), the discriminant is b2 - 4ac. This discriminant can be positive, zero, or negative.
Create three unique equations where the discriminant is positive, zero, or negative. For each case, explain what this value means to the graph of y = ax2 + bx + c.
Click here to see answer by LifeDeathnCandy(5) |
Question 33311: I am stuck on the following quadratic equation:
2x^2-3x-1=0
I move the 1 over like this:
2x^2-3x=1
and that's where I get stuck: how do you create a third term to the left side of the equation like that will later generate -3x? Do you take square half the value of the second term? (-3x / 2)^2, which results in 9/4x?
Thanks so much for your help.
Click here to see answer by stanbon(57361) |
Question 33304: I'm having difficulty solving the following quadratic equation:
(a-2 / a+2) - (a+2 / a-1) = (a^2-32 / a^2+a-2)
By finding the common denominator, I was able to reduce this equation down to:
a^2+7a=30
But at this point I am stuck. How do you proceed to get to the two values for a? I know you have to add something to both sides, and isn't it supposed to be half of the middle term squared? (7/2)^2 ? The book just provides the two final solutions for a without telling you how it got them.
Thanks for your help!
Click here to see answer by checkley71(8403) |
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