SOLUTION: {{{ 3y^2-7y-5=0 }}}

Algebra.Com
Question 99891:
Found 2 solutions by jim_thompson5910, checkley71:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Let's use the quadratic formula to solve for y:


Starting with the general quadratic



the general solution using the quadratic equation is:





So lets solve ( notice , , and )




Plug in a=3, b=-7, and c=-5



Negate -7 to get 7



Square -7 to get 49 (note: remember when you square -7, you must square the negative as well. This is because .)



Multiply to get



Combine like terms in the radicand (everything under the square root)



Simplify the square root (note: If you need help with simplifying the square root, check out this solver)



Multiply 2 and 3 to get 6

So now the expression breaks down into two parts

or


Now break up the fraction


or


Simplify


or


So these expressions approximate to

or


So our solutions are:
or

Notice when we graph (just replace y with x), we get:



when we use the root finder feature on a calculator, we find that and .So this verifies our answer

Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!
3Y^2-7Y-5=0
USING THE QUADRATIC EQUATION WE GET:

X=(7+-SQRT[-7^2-4*3*-5])/2*3
X=(7+-SQRT[49+60])/6
X=(7+-SQRT109)/6
X=(7+-10.44)/6
X=(7+10.44)/6
X=17.44/6
X=2.9 ANSWER.
X=(7-10.44)/6
X=-3.44/6
X=.57 ANSWER.

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