SOLUTION: {{{ 3y^2-7y-5=0 }}}
Algebra.Com
Question 99891:
Found 2 solutions by jim_thompson5910, checkley71:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Let's use the quadratic formula to solve for y:
Starting with the general quadratic
the general solution using the quadratic equation is:
So lets solve ( notice , , and )
Plug in a=3, b=-7, and c=-5
Negate -7 to get 7
Square -7 to get 49 (note: remember when you square -7, you must square the negative as well. This is because .)
Multiply to get
Combine like terms in the radicand (everything under the square root)
Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
Multiply 2 and 3 to get 6
So now the expression breaks down into two parts
or
Now break up the fraction
or
Simplify
or
So these expressions approximate to
or
So our solutions are:
or
Notice when we graph (just replace y with x), we get:
when we use the root finder feature on a calculator, we find that and .So this verifies our answer
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
3Y^2-7Y-5=0
USING THE QUADRATIC EQUATION WE GET:
X=(7+-SQRT[-7^2-4*3*-5])/2*3
X=(7+-SQRT[49+60])/6
X=(7+-SQRT109)/6
X=(7+-10.44)/6
X=(7+10.44)/6
X=17.44/6
X=2.9 ANSWER.
X=(7-10.44)/6
X=-3.44/6
X=.57 ANSWER.
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