SOLUTION: What is the equation in standard form of the parabola whose vertex is (2,5), which passes through the point (-5,2)

Question 998237: What is the equation in standard form of the parabola whose vertex is (2,5), which passes through the point (-5,2)
Found 2 solutions by stanbon, josgarithmetic:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
What is the equation in standard form of the parabola whose vertex is (2,5), which passes through the point (-5,2)
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Vertex Form:: y = a(x-h)^2+k
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Using vertex (2,5) ::
y = a(x-2)^2 + 5
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Using point (-5,2)
2 = a(-5-2)^2+5
2 = a(54)
a = 1/27
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Ans: y = (1/27)(x-2)^2+5
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Cheers,
Stan H.
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Answer by josgarithmetic(39616) (Show Source): You can put this solution on YOUR website!
Standard Form (but which direction?), .

Vertex is given.

A point on graph is included. Solve for factor a.

ANSWER:
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