SOLUTION: I have a problem that seems simple but I'm having an issue solving it. The problem is:
A=l*w
Length of rectangle 5" more then width. Area is 66". What is length and width? L=w+5
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Question 997800: I have a problem that seems simple but I'm having an issue solving it. The problem is:
A=l*w
Length of rectangle 5" more then width. Area is 66". What is length and width? L=w+5
66= w(w+5) I write this out as w^2+5w-66. Then I factor this so (w+11)(w-6) but I don't know how to finish. Can you help me?
Found 2 solutions by josgarithmetic, MathLover1:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
The quadratic should have come as a step in and then factored,
NOW use Zero Product Rule, and one solution will be meaningless and the other will be meaningful.
Either w+11=0 OR w-6=0.
Which one is needed?
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
Length of rectangle more then width. Area is . What is length and width?
solutions:
if =>=> disregard negative solution because we are looking for the width and it cannot be negative number
if =>
now find the length: =>=>
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