SOLUTION: I am trying to find the vertex but I'm having a problem finding both the x and the y coordinate. The equation I am working on is y=x^2+10x. Can you help me

Question 997346: I am trying to find the vertex but I'm having a problem finding both the x and the y coordinate. The equation I am working on is y=x^2+10x. Can you help me
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
The vertex x value is -b/2a, where ax^2+bx+c=0
Here, a=1 and b=10
The x value of the vertex is -10/2= -5
That makes the y value -25
the vertex is at (-5,-25)

RELATED QUESTIONS
I am trying to solve a function that I must graph and I am having a problem solivng the... (answered by stanbon)

I am having problems finding the vertex of this problem.. could someone please help. (answered by jim_thompson5910)

i am trying to find the y coordinate of the vertex. the x is -2 and when i plug it in to (answered by rfer)

For the following: f(x)= 5x^2-70x+227, I need to find: Shifted Form Range x-Intercept (answered by MathLover1)

I am trying to find the vertex for the function: f(x)=x^2 + x - 2. I believe the axis of... (answered by jim_thompson5910)

I am trying to test an equation for symmetry. The equation is x^2 - y^3 + 4. I am... (answered by stanbon)

I am trying to test an equation for symmetry. The equation is x^2 = y^3 + 4. I am... (answered by MathTherapy)

Please help!! I am trying to find out how to do the following problem. Write a equation... (answered by fractalier)

I have the equation y=-x^2-8x-15 and i am trying to graph it. How do I find the... (answered by edjones)