SOLUTION: Use a graphing utility to find or approximate solution(s) of the given equation.
20x+5=24x^2+6x
Algebra.Com
Question 997023: Use a graphing utility to find or approximate solution(s) of the given equation.
20x+5=24x^2+6x
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
Solve for x:
20x+5= 24x^2+6x
Subtract 24x^2+6x from both sides:
-24x^2+14x+5= 0
Factor the left side:
-((4x+1)(6x-5))= 0
Multiply both sides by -1:
(4x+1)(6 x-5)= 0
Now we have:
4x+1= 0 or 6x-5= 0
Subtract 1 from both sides:
4x= -1 or 6x-5= 0
On the first equation, divide both sides by 4. On the second equation, add 5 on both sides:
x= -1/4 or 6x= 5 On the second equation, divide both sides by 6:
x= -1/4 or x= 5/6
Try these numbers and see which one makes your equation an equality. Only one will work, that will be your answer.
Re. graphing, if you don't have a graphing calculator and don't know how to graph using a spreadsheet like Excel maybe you can find a graphing calculator online.
RELATED QUESTIONS
Use a graphing utility to approximate any relative minimum or maximum points of... (answered by Fombitz)
1. Use a graphing utility to approximate the real solutions, if any, of the given... (answered by josgarithmetic,math_tutor2020)
Use a graphing utility to approximate the real solutions, if any, of the given equation... (answered by josmiceli,Alan3354)
5sinx+2cosx=0 Use a graphing utility to approximate the solutions of the equation in the... (answered by Fombitz)
Use a graphing utility to approximate (to two decimals) any relative minimum or maximum... (answered by Earlsdon)
Use the Intermediate Value Theorem and a graphing utility to find graphically any... (answered by jsmallt9)
Use a graphing utility to approximate the solutions of the equation in the interval[0,... (answered by Fombitz)
use a graphing utility to approximate the real solutions, if any of the given equation... (answered by stanbon)
graph the equation on the graph by completing the table and plotting the points You may... (answered by stanbon)