SOLUTION: I am trying to solve this problem using the quadratic formula but I need help. here is the problem: x^2+12=0

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Question 996252: I am trying to solve this problem using the quadratic formula but I need help. here is the problem:
x^2+12=0
Found 3 solutions by Alan3354, fractalier, LinnW:
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
I am trying to solve this problem using the quadratic formula but I need help. here is the problem:
x^2+12=0
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -48 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -48 is + or - .

The solution is , or
Here's your graph:

=================
x^2+12=0
x^2 = -12
x = ħsqrt(-12) = ħ2sqrt(3)i
Answer by fractalier(6550)   (Show Source): You can put this solution on YOUR website!
For x^2+12=0, the a=1, b=0, and c=12.
Thus, from the quadratic formula,
x = [-0 +- SQRT(0^2 - 4(1)12)] / 2
x = +- SQRT(-48) / 2
x = +- 4i*SQRT(3) / 2
x = +- 2i*SQRT(3)
Answer by LinnW(1048)   (Show Source): You can put this solution on YOUR website!
First the quadratic formula

Our equation is
The a in the formula is the coefficient of the square term
so for our equation, a = 1
Since our equation does not have a middle term, b = 0
c is the value of the constant which for us is 12
Substituting we get






Since we have the square root of a negative number we have no real root
Notice that we could have solved more easily.
Take our equation,
add -12 to each side

Take the square root of each side and we get
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