Good Morning. I am trying to figure out how to complete the square for this problem but I am having no luck My problem is:
3x^2-13x+4=0. I know I have to divide each term by 3 which would give me:
x^2-13/3x+4/3=0. Then I subtract 4/3 on both sides to get x^2-13/3x=-4/3. I multiply -13/3xand 1/2 to get -13/6x then I square it to get 169/36 which I add to both sides of the equation.
x^2-13/3x+169/36=-4/3+169/36. Here is where I'm having a hard time and are looking for your help.
------ This is where you are, Great job in getting to this point!
------ Factoring left-side of equation
----- Changing fraction on right to a common denominator, 36
----------- Summing right side of equation
----- Taking the square root of both sides
------- Adding to both sides
OR
OR