SOLUTION: write a quadratic equation whose solutions are 1+2i and 1 - 2i the equation is x^2-_x+_=0

Algebra.Com
Question 987166: write a quadratic equation whose solutions are 1+2i and 1 - 2i
the equation is x^2-_x+_=0

Answer by ikleyn(52776)   (Show Source): You can put this solution on YOUR website!
.
(x - (1+2i))*(x - (1-2i)).

The constant term is the product  (1+2i)*(1-2i) = - = 1 - 4*(-1) = 1 + 4 = 5.

The coefficient at  x  is  -[(1+2i) + (1-2i)] = -2.

Hence,  the quadratic equation is

- + = .


RELATED QUESTIONS

write quadratic equation whose solutions are 1+2i and 1-2i The equation is x^2-_x+_=0 (answered by ikleyn)
Write a quadratic equation whose solutions are 2i and -2i in standard... (answered by josmiceli)
Write the quadratic equation witha lead coefficient of 1 whose roots are 3+2i and... (answered by ankor@dixie-net.com)
1. The solution of a polynomial equation are shown below. x = 3+4i x = 5 What is... (answered by josgarithmetic)
square root of 18x2 multiplied by the square root of 12x 2) Divide 3+2i/1-1i 3) (answered by tran3209)
What is the quadratic equation that has a one root of 1+2i? my work:... (answered by jim_thompson5910,MathTherapy)
The question asks to find a quadratic equation whose solutions are +2i and -2i. How do... (answered by ewatrrr,TimothyLamb)
Hi there, I have to find a degree 3 polynomial whose coefficients are real numbers and... (answered by robertb,stanbon)
Question: If Following Are The Solutions Of 2 Quadratic Equations Equation 1: Real... (answered by sabanasir)