SOLUTION: The product of two consecutive odd integers is 58 less than the square of the next consecutive integer. Find the three integers.

Algebra.Com
Question 987129: The product of two consecutive odd integers is 58 less than the square of the next consecutive integer. Find the three integers.
Answer by macston(5194)   (Show Source): You can put this solution on YOUR website!
.
x and x+2 are consecutive odd integers. x+4=next consecutive odd integer.
.




ANSWER 1: the first integer is 7.
second integer=x+2=7+2=9
ANSWER 2: The second integer is 9.
third integer=x+4=7+4=11
ANSWER 3: The third integer is 11.
.
CHECK:




RELATED QUESTIONS

The product of two consecutive odd integers is 58 less than the square of the next... (answered by mananth)
4. The Product of two consecutive odd integers is 58 less than the square of the next... (answered by josgarithmetic)
The product of two consecutive odd integers is 58 less than the square of the next... (answered by mananth)
The product of two consecutive odd integers is 10 more than the square of the smaller... (answered by stanbon,drj)
Find the three consecutive odd integers such that the product of the first and third... (answered by ankor@dixie-net.com)
Find the three consecutive odd integers such that the product of the first and third... (answered by Mathtut)
The product of two consecutive integers is 16 less than the square of the next larger... (answered by multiplier)
The product of two consecutive positive odd integers is 38 less than the square of the... (answered by ad_alta)
The product of two consecutive odd integers is 22 less than the square of the greater... (answered by algebrahouse.com)