SOLUTION: Find all real or imaginary solutions to each equation. Use the method of your choice.
3v^2 + 4v - 1 = 0
Algebra.Com
Question 98540: Find all real or imaginary solutions to each equation. Use the method of your choice.
3v^2 + 4v - 1 = 0
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Let's use the quadratic formula to solve for v:
Starting with the general quadratic
the general solution using the quadratic equation is:
So lets solve ( notice , , and )
Plug in a=3, b=4, and c=-1
Square 4 to get 16
Multiply to get
Combine like terms in the radicand (everything under the square root)
Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
Multiply 2 and 3 to get 6
So now the expression breaks down into two parts
or
Now break up the fraction
or
Simplify
or
So these expressions approximate to
or
So our solutions are:
or
Notice when we graph (just replace v with x), we get:
when we use the root finder feature on a calculator, we find that and .So this verifies our answer
RELATED QUESTIONS
Find all real or imaginary solutions to each equation. Use the method of your choice.... (answered by jim_thompson5910)
86.) Find all real or imaginary solutions. use the method of your choice.
3v^2 + 4v -... (answered by Fombitz)
Find all real or imaginary solutions to the eqyation.... (answered by Fombitz)
Find all real or imaginary solutions to each equation.
Use the method of your choice.
(answered by nerdybill)
Find all real or imaginary solutions to each equation.
Use the method of your choice.
(answered by nerdybill)
Find all real or imaginary solutions to each equation. Use the method of your choice.
(answered by checkley71)
how do i find all real or imaginary solutions?... (answered by Alan3354)
80.)Find all real or imaginary solutions. use the method of your choice.
w^2 = -225
(answered by checkley77)
80. Find all real or imaginary solutions to each equation. Use the method of your choice. (answered by richwmiller,drk)