SOLUTION: The area of a garden is 160 m2. Suppose the length of the length of the garden is 3 m more than twice its width. What is the length of the garden?

Question 984419: The area of a garden is 160 m2. Suppose the length of the length of the garden is 3 m more than twice its width. What is the length of the garden?

Found 2 solutions by solver91311, Timnewman:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Let represent the width. Then represents the length. Since the area of a rectangle is the length times the width,

Which is to say

Solve the quadratic for and then calculate

John

My calculator said it, I believe it, that settles it

Answer by Timnewman(323) (Show Source): You can put this solution on YOUR website!
Hi dear,
Let L=lengh
w=width
If L*w=160----(1)
and L=3+2w---(2)
put (2) in (1)
(3+2w)w=160
2w�+3w-160=0
solving quadratic equation,

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=1289 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 8.22566153550812, -9.72566153550812. Here's your graph:

Since w=8 aproximately,
put w=8 in in equ 2
there L=3+2*8
L=19m
the lenght is 19m
hope this helps;
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