SOLUTION: One solution of {{{ kx^2+3x-k=0 }}} is -2. Find the other solution using quadratic formula (or using other ways)

Question 982938: One solution of is -2. Find the other solution using quadratic formula (or using other ways)
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
for x = -2, we have
k*(-2)^2 + 3*(-2) - k = 0
4k -6 - k = 0
3k = 6
k = 2, therefore
2x^2 +3x -2 = 0
x = (-3 + square root(9 - 4*(2)*(-2))) / 4 = 0.5
x = (-3 - square root(9 - 4*(2)*(-2))) / 4 = -2
therefore,
the solutions for x are x = -2, x = 0.5

RELATED QUESTIONS
One solution of {{{kx^2}}}-7x+k=0 is 4. Find the other... (answered by jim_thompson5910)

One solution of kx^2-5x+k=0 is 3. Find the other... (answered by bucky)

Find the range of k for which the quadratic equation x^2-kx+3k-2=0 has two different... (answered by KMST)

One solution of 2x^2+11x+k=0 is -5. Find the other... (answered by ankor@dixie-net.com)

One solution of 2x^2+11x+k=0 is -5. Find the other... (answered by checkley75)

For which value or values of k, if any, does the quadratic equation in x, (k-8)x^2+kx -1 (answered by ankor@dixie-net.com)

Solve by using the quadratic formula. The solution set is { , } or is solution set 0? (answered by Deina)

Please help me solve this problem: Find the value of k. {{{6x^2+kx-6=0}}} ; one root is (answered by Edwin McCravy)

If x=3,is a solution of the equation X^2+kx+15, find the value of k .Hence find the... (answered by josgarithmetic,ikleyn)