SOLUTION: Quadratic equation parabola. .
y=3-15x-3x^2
Algebra.Com
Question 982200: Quadratic equation parabola. .
y=3-15x-3x^2
Answer by josgarithmetic(39621) (Show Source): You can put this solution on YOUR website!
What do you want? Solve, graph, general into standard form, intercepts?
response: most of it.
MISTAKE IS NOW FIXED (it was a mistake in sign.)
COMPLETE REDO----....
Term to complete the square is .
------standard form equation, so now easier to graph.
This is a parabola, concave downward with vertex as a maximum.
The leading coefficient is NEGATIVE, telling you that the vertex will be a maximum. (the negative 3).
Vertex is (-5/2,87/4), which is read directly from the standard form equation.
ROOTS OR ZEROS
-------the roots, zeros, x-intercepts
y-AXIS INTERCEPT
where x=0
-----back to the original equation because this will be easier.
--------the y-axis intercept
Graph should look like this:
NOTE: This graph is coded correctly but is not displaying correctly, so
I am not including the rendering tags. Use a graphing tool or such software to
see the graph properly.
graph(300,300,-10,10,-3,24,-3x^2-15x+3)
somewhat different scaling for x versus y axes
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