SOLUTION: {{{2x^2-(4÷sqrt (13)) x+2sqrt (13) =0}}}

Algebra.Com
Question 980749: AMP Parsing Error of [2x^2-(4÷sqrt (13)) x+2sqrt (13) =0]: Invalid expression. Closing bracket expected ÷sqrt(13))x+2\sqrt(13)=0 at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 187. .
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
The dot over dot division symbol stopped the rendering.




First adjust the second term:



The original expression is equivalent to




Formula for general solution of quadratic equation,



you might be able to simplify this further, at least


RELATED QUESTIONS

x^2+6x-4=0 Please help me solve? x^2+6x-4=0 --- Use Quadratic Formula: x = [-6... (answered by stanbon,juicebae)
x^2-2x-13=0 (answered by drj)
x^2-2x-13=0 (answered by vheroli)
{{{ x^2 -2/sqrt( 13 )x + sqrt(13 ) = 0... (answered by solver91311)
1. y = 2sqrt(x + 3) by graphing 5 points. Use the endpoint of the function as your first (answered by scott8148)
use the quadratic formula to solve:3x^2+2x-4=0? A)x=-1 B)x=sqrt(13) C)x=-1-sqrt(13)... (answered by jim_thompson5910)
solve x^2 - 2x - 13 =... (answered by Stitch,checkley77)
I need to solve this equation for x: sqrt(2x-1) - sqrt(x-1) = 1 This is what I have (answered by solver91311)
x^2-x-13=0 (answered by jim_thompson5910)