SOLUTION: I really need help with the detail of solving this problem. Can someone please show me the step by step process in figuring out this problem? I have tried to calculate it man

Question 980221: I really need help with the detail of solving this problem. Can someone please show me the step by step process in figuring out this problem?
I have tried to calculate it many times and cannot for the life of me come up with the correct answer.
I am familiar with the quadratic formula but for some reason cannot get it to work for this problem.
�An object is thrown directly upward from a starting height of 25 ft and a starting velocity of 85 ft per second. The following function describes the height of the object with respect to the time, t.�
h(t) = -16t2 + 85t + 25
How long does it take before the object reaches the ground? Round you answer to
the nearest hundredths place.
The answer is 5.59.

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
�An object is thrown directly upward from a starting height of 25 ft and a starting velocity of 85 ft per second. The following function describes the height of the object with respect to the time, t.�
h(t) = -16t2 + 85t + 25
How long does it take before the object reaches the ground? Round you answer to
the nearest hundredths place.
The answer is 5.59.
====================
Use ^ (Shift 6) for exponents.
h(t) = -16t^2 + 85t + 25
It hits the ground when h(t) = 0
---
h(t) = -16t^2 + 85t + 25 = 0
Solve for t

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=8825 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: -0.27942097313374, 5.59192097313374. Here's your graph:

=================
t = ~ 5.59 seconds
----
Ignore the negative solution.

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