SOLUTION: Find a such that f(x)=ax^2 -4x +3 has a maximum value of 12
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Question 975177: Find a such that f(x)=ax^2 -4x +3 has a maximum value of 12
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ =\ ax^2\ -\ 4x\ +\ 3)
is a parabola with vertex at )
where 
and )
.
Evaluate )
, set the resulting polynomial in 
equal to 12, and then solve for
Hint: Since you are looking for a maximum, the parabola must open downward, which is to say that 
. If you don't come up with a negative value for , check your arithmetic.
John
My calculator said it, I believe it, that settles it
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