SOLUTION: I understand that this problem, x^2=8x-16 should be written like this:
x^2-8x+16=0.
But how do i solve this: x^2+12x=3x-18
Algebra.Com
Question 971174: I understand that this problem, x^2=8x-16 should be written like this:
x^2-8x+16=0.
But how do i solve this: x^2+12x=3x-18
Found 2 solutions by josh_jordan, josgarithmetic:
Answer by josh_jordan(263) (Show Source): You can put this solution on YOUR website!
First thing you need to to is get everything on one side of the equal sign and put a zero on the other side. So,
x^2 + 12x = 3x - 18
First, subtract 3x from both sides, giving us:
x^2 + 12x - 3x = 3x - 3x - 18 -----> x^2 + 9x = -18
Next, add 18 to both sides:
x^2 + 9x + 18 = 18 - 18 -----> x^2 + 9x + 18 = 0
Now, factor the left side of the equation, giving us
(x + 6)(x + 3) = 0
Set each set of parenthesis equal to 0:
x + 6 = 0
x + 3 = 0
Solve each for x:
x = -6
x = -3
So, x = -6 and -3
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Meaning what? You want to put into general form, like the first example? You already learned the
method and the skills.
and you want in the format . Nothing tough to do or to know.
That is factorable in case you really want to SOLVE it. You can factor and then
use the Zero Product Principle.
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