SOLUTION: 3x^2+40x-128=0
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Question 970265: 3x^2+40x-128=0
Found 2 solutions by ankor@dixie-net.com, MathLover1:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
3x^2 + 40x - 128 = 0
you can use the quadratic formula a=3; b=40; c=-128, but this will factor to
(3x - 8)(x + 16) = 0
3x = 8
x = 2
and
x = -16
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
....write as
...group
solutions:
if , then
if , then
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