SOLUTION: 2x+9times the sq.root of x=5

Question 96843: 2x+9times the sq.root of x=5
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
2x+9sqrt(x) = 5
9sqrt(x) = 5-2x
Square both sides to get:
81x = 25-20x+4x^2
4x^2-101x+25=0
x = [101 +- sqrt(101^2-4*4*25)]/8
x = [101 +- sqrt(9801)]/8
x = [101 +- 99]/8
x = 1/4 or x = 25
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Cheers,
Stan H.
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