SOLUTION: Find two integers whose product is 105 such that one of the integers is one more than twice the other integer.

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Question 965436: Find two integers whose product is 105 such that one of the integers is one more than twice the other integer.
Answer by macston(5194)   (Show Source): You can put this solution on YOUR website!
.
x and y are the integers
x=2y+1
xy=105 Substitute for x
(2y+1)(y)=105 Subtract 105 from each side
2y^2+y-105=0
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=841 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 7, -7.5. Here's your graph:

y=7 ANSWER 1: One of the integers is 7
x=2y+1=2(7)+1=14+1=15 ANSWER 2: The other integer is 15


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