SOLUTION: What is the vertex and axis of symmerty for y=-2x^2+16x-16

Question 962767: What is the vertex and axis of symmerty for y=-2x^2+16x-16
Found 2 solutions by lwsshak3, MathLover1:
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
What is the vertex and axis of symmetry for
y=-2x^2+16x-16
vertex form of equation for a parabola: y=A(x-h)^2+k, (h,k)=coordinates of the vertex
complete the square:
y=-2(x^2-8x+16)+32-16
y=-2(x-4)^2+16
vertex: (4, 16)
axis of symmetry: x=4
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
to find the vertex, first write your equation in vertex form where and are and coordinates of the vertex
....complete the square

so, and and vertex is at (,)
the axis of symmetry is the line that runs down its 'center' and divides the graph into two perfect halves; in your case the axis of symmetry is a line

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