SOLUTION: Can I have help please "Solve by factoring {{{2x^2-7x-4=0}}}" We are using the zero product property, but there are no multiples of 4 that goes into 7.

Question 962634: Can I have help please
"Solve by factoring
"
We are using the zero product property, but there are no multiples of 4 that goes into 7.
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
2x^2 - 7x - 4 = 0
multiply 2 * 4 to get 8
look for the factors of 8 that add up to or subtract from each other to get -7
since the coefficient of the x term is negative and the coefficient of the constant term is also negative, you will be looking for factors that subtract from each other to get 7.

8 * 1 = 8 and 8 - 1 = 7
they look like they'll do.

split the middle term into -8x and +x to get:
2x^2 - 8x + x - 4 = 0
associate the first two terms together and the last two terms together to get:
(2x^2 - 8x + (x - 4) = 0
factor the first associated terms so that (x - 4) is one of the factors.
you will get:
2x * (x-4) + (x-4) = 0
this is equivalent to:
2x * (x-4) + 1 * (x-4) = 0
factor out the common term of (x-4) to get:
(2x + 1) * (x-4) = 0
those are your factors.
read this tutorial on factoring.
it should help.
http://www.purplemath.com/modules/factquad.htm

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