SOLUTION: sorry to bother so confused with algebra ..
(exponents pretend ^5)
What solution do 2x^2 - 13x +21 = 0 and 2x^+ 9x-56 =0 have in
common? Round your answer to the nearest
Algebra.Com
Question 950449: sorry to bother so confused with algebra ..
(exponents pretend ^5)
What solution do 2x^2 - 13x +21 = 0 and 2x^+ 9x-56 =0 have in
common? Round your answer to the nearest tenth if necessary.
Found 3 solutions by josgarithmetic, macston, MathLover1:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Using general solution for quadratic equation.
D1 and D2 are the discriminants of each equation.
E1,
E2,
E1,
or
or
E2,
or
or
Common to both equations,
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
Subtract from each side.
-13x+21=9x-56 Add 56 to each side.
-13x+77=9x Add 13x to each side.
77=22x Divide each side by 22.
77/22=x
3.5=x ANSWER: The common solution is x=3.5.
CHECK
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
solutions:
=>
solutions:
=>
both functions have one root in common and that is
means, if you plug in both equations will be equal to zero, so graphs intersect in a point (,)
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