SOLUTION: (pretend exponent ^4) 3. The product of two consecutive integers, n and n + 1, is 42. What is the positive integer that satisfies the situation?

Question 950439: (pretend exponent ^4)
3. The product of two consecutive integers, n and n + 1, is 42. What is the
positive integer that satisfies the situation?

Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
n(n+1)=42
n^2+n=42
n^2+n-42=0

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=169 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 6, -7. Here's your graph:

The positive answer is 6.
ANSWER: The positive integer that satisfies the situation is 6.
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