SOLUTION: Write the quadriatic equation below in standard form. Identify the value of a, b, and c. (3x+2)(x-6)=0 a= b= c=

Question 950135: Write the quadriatic equation below in standard form. Identify the value of a, b, and c.
(3x+2)(x-6)=0
a=
b=
c=
Found 3 solutions by amarjeeth123, josgarithmetic, MathTherapy:
Answer by amarjeeth123(569)   (Show Source): You can put this solution on YOUR website!
(3x+2)(x-6)=0
3x^2-18x+2x-12=0
3x^2-16x-12=0
Comparing with ax^2+bx+c=0 we get
a=3
b=-16
c=-12
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
"standard form"?

-
a=3
b=-16
c=-12

You could try to avoid Completing the Square process since your equation is given as factored.
Roots are -2/3 and 6.
Symmetry axis is in the middle.

Axis of Symmetry, FOR THE FUNCTION, not just the given equation.

y for the vertex:

-----?

Finish by filling in the standard form information.
,
?
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Write the quadriatic equation below in standard form. Identify the value of a, b, and c.
(3x+2)(x-6)=0
a=
b=

(3x + 2)(x - 6) = 0
Standard form:

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