SOLUTION: the equation h(t)=-16t^2+864t models the path of a rocket shot into the air. after how many seconds does the rocket hit the ground?

Question 949274: the equation h(t)=-16t^2+864t models the path of a rocket shot into the air. after how many seconds does the rocket hit the ground?
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
h(t)=-16t^2+864t
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When h(t) = 0 where t > 0
Solve for t
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h(t) = 0 at launch and at impact

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
the equation h(t)=-16t^2+864t models the path of a rocket shot into the air. after how many seconds does the rocket hit the ground?
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Height is zero when the rocket hits the ground.
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Solve:
-16t^2 + 864t = 0
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Factor:
-16t(t - 54) = 0
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Positive solution:
t = 54 seconds
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Cheers,
Stan H.
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