SOLUTION: I need help solving these two problems.
x^2 – 3x = -6x – 1
x^2 – 10x – 1 = -10
Algebra.Com
Question 94606: I need help solving these two problems.
x^2 – 3x = -6x – 1
x^2 – 10x – 1 = -10
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
X^2-3X=-6X-1
X^2-3X+6X+1=0
X^2+3X+1=0
USING THE QUADRATIC EQUATION:
X=(-3+-SQRT[3^2-4*1*1])/2*1
X=(-3+-SQRT[9-4])/2
X=(-3+-SQRT5)/2
X=(-3+-2.236)/2
X=(-3+2.235)/2
X=-.763/2
X=-.382 ANSWER.
X=(-3-2.236)/2
X=-5.236/2
X=-2.618 ANSWER.
RELATED QUESTIONS
I need help with three math problems:
#1.) 4x^2 + 10x +6
#2.) x^2 - 5x+6 = 0
(answered by mananth)
i need help solving these 2 linear equation problems. they both must be solved using... (answered by venugopalramana)
Hello,
I need help with solving these inequality problems please.
100 > -5/3x + 6... (answered by rfer)
I need a little help with these 2 problems in putting them in rational form.
-3(x +... (answered by Alan3354)
Please help me with these problems
1. x^2-6x-7
__________
x^2 - 1
2. x^2... (answered by Earlsdon)
solve by factoring
1. x^2 +7x+10=0
2 3x^2-6x=0
only two problems to solve. need (answered by jim_thompson5910)
Need help on solving these two problems, thanks =0)
1. -9x+20=-2x
2. 2x^2-5=3x (answered by corrie21)
I need help with a few problems. These are my hardest ones.
1. -3 = 7 - 4y
2. 2x +... (answered by bonster)
i need to find the x-intercept, y-intercept, axis of symmetry, and vertex of these two... (answered by edjones)