SOLUTION: I am 32 and just now going back to college, so it has been um..oh about 15 years since I even did any type of algebra problem. This is all new territory for me. Here is the probl

Question 94574This question is from textbook College Algebra
: I am 32 and just now going back to college, so it has been um..oh about 15 years since I even did any type of algebra problem. This is all new territory for me. Here is the problem as it was presented to me.
Find k such that the equation x(2)^-kx+4=0 has a repeated real solution.
I am not understanding the concept of real solution, I think.
Erica This question is from textbook College Algebra

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find k such that the equation x(2)^-kx+4=0 has a repeated real solution.
The discriminant tells you.
If b^2-4ac = 0 there will be two equal Real Number solutions.
Your Problem:
a=1,b=-k,c=4
b^2-4ac = (-k)^2-4*1*4 =k^2-16
k^2-16 0
(k-4)(k+4) >0
True when k=4 and when k=-4
Conclusion: You will have two equal Real Number solutions when
k=4 and when k=-4.
==============
Cheers,
Stan H.
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