SOLUTION: Find the vertex and intercepts for each quadratic function, and sketch its graph y = x^2 + 4x y = x^2 + 2x - 24 I have not clue what formula to use. HELP! Thanks i

Question 9425: Find the vertex and intercepts for each quadratic function, and sketch its graph

y = x^2 + 4x

y = x^2 + 2x - 24

I have not clue what formula to use. HELP! Thanks in advance.
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
y = x^2 + 4x
y = x(x+4) = 0
X-intercepts at x=0 and x= -4

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=16 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 0, -4. Here's your graph:

y = x^2 + 2x - 24
Y = (x+ 6)(x -4)
X-intercepts at x= -6 and x= 4

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=100 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 4, -6. Here's your graph:

R^2 at SCC with help from "i from Chicago"
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