SOLUTION: Write a quadratic equation such that the sum of its roots is 6 and the product of its roots is -27.

Question 941191: Write a quadratic equation such that the sum of its roots is 6 and the product of its roots is -27.
Found 2 solutions by richard1234, stanbon:
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
x^2 - 6x - 27 = 0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Write a quadratic equation such that the sum of its roots is 6 and the product of its roots is -27.
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Since the roots are [-b+sqrt(b^2-4ac)]/2a and [-b-sqrt(b^2-4ac)]/(2a)
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Sum of the roots is 2[-b/(2a)] = -b/a
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Product is (b^2-(b^2-4ac)]/(4a^2) = 4ac/4a^2 = c/a
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Equation:
y = x^2 - (sum of roots)x + (product of roots)
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y = x^2 -6x -27
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Cheers,
Stan H.
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