SOLUTION: f(x)=x^2+2x-3 Vertex: Axis of Sym: Y-int: D: R:

Question 940628: f(x)=x^2+2x-3
Vertex:
Axis of Sym:
Y-int:
D:
R:
Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
f(x)=x^2+2x-3
Vertex:
x = -b/(2a) = -2/(2) = -1
f(-1) = (-1)^2 -2 - 3 = -4
Vertex:: (-1,-4)
------------------------
Axis of Sym:
x = -1
-----
Y-int:
f(0) = -3
-------
Domain::: All Real Numbers.
Range::: y >= -4
-------------------------
Cheers,
Stan H.
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Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!

First write it in vertex form: complete square

The vertex is (,) => minimum (parabola opens up)
The axis of sym. is
Y-int:
D: (R}}} all real numbers
R: { element : }

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