SOLUTION: transform the quadratic function y=-2x^2-12x-10 into vertex form. find the vertex, x and y intercepts.

Question 936233: transform the quadratic function y=-2x^2-12x-10 into vertex form. find the vertex, x and y intercepts.
Found 3 solutions by ewatrrr, srinivas.g, MathLover1:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
Previously Posted
y= -2x^2-12x-10 P(0, -10) y-intercept
y = -2(x+3)^2 + 18 - 10
y = -2(x+3)^2 + 8
V(-3,8)
......
0 = -2(x+3)^2 + 8
4 =(x+3)^2
� 2 = x+3
-3 � 2 = x
P(-5,0) and P(-1,0) x-intercepts

Answer by srinivas.g(540)   (Show Source): You can put this solution on YOUR website!
step 1 : determination of vertex

vertex form
vertex =(h,k)
hence vertex (h,k) =(-3,8)
step 2
determination of y-intercept:
keep x=o in the y= -2x^2-12x-10
y= -2*0-12*0 -10
y= -10
hence y-intercept = -10
step 3
Determination of x-intercept:
keep y= 0 in y= -2x^2-12x-10

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=64 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: -5, -1. Here's your graph:

hence x-intercepts are -5, -1

Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!

the vertex form:

vertex is at (,)

y-intercept is
x-intercept is:

solutions:
if =>
if =>
so, x-intercepts are: and

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