SOLUTION: If y varies directly as x and inversely as z^2, and y = 3 when x = 2 and z = 4, what is the value of x when y = 9 and z = 4?

Question 93431This question is from textbook
: If y varies directly as x and inversely as z^2, and y = 3 when x = 2
and z = 4, what is the value of x when y = 9 and z = 4? This question is from textbook

Answer by psbhowmick(878) (Show Source): You can put this solution on YOUR website!
'y' varies directly as 'x' and inversely as 'z^2'.
Hence, _______ (1)
Now, y = 3 when x = 2 and z = 4,
Substituting the values of 'x', 'y' and 'z' in (1)

So (1) becomes
_____ (2)

Substituting the values of 'y' and 'z' in (2)

The reqd. value of 'x' when y = 9 and z = 4 is 6.
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