SOLUTION: Find the equation of the parabola that passes through (0,0) (6,0) (3,27) y=0; when x=6; and y=0 when x=0. -27=k(x-6)(x-0) k=9/2 =9/2(x^2-6x) =9/2x^2-27 However, the a

Question 932492: Find the equation of the parabola that passes through (0,0) (6,0) (3,27)
y=0; when x=6; and y=0 when x=0.
-27=k(x-6)(x-0)
k=9/2
=9/2(x^2-6x)
=9/2x^2-27
However, the answer given is 3x^2-18x
Where have I gone wrong?

Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
(0,0) (6,0) (3,-27)* Assuming it is '-27'
y = a(x-6)(x-0) Good Work
y = a(x^2 - 6x)
...
P(3,-27)
-27 = a(-9)
3 = a
..........
y = 3(x^2-6x)
y = 3x^2 - 18x

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