SOLUTION: Find the exact coordinates for the vertex of the function y=3x^2+6x+1

Question 932194: Find the exact coordinates for the vertex of the function y=3x^2+6x+1

Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
3x^2 + 6x + 1 = 0
---
the above quadratic equation is in standard form, with a=3, b=6 and c=1
---
to solve the quadratic equation, by using the quadratic formula, copy and paste this:
3 6 1
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
---
the quadratic has a vertex (a minimum) at:
---
( -1, -2 )
---
Solve and graph linear equations:
https://sooeet.com/math/linear-equation-solver.php
---
Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
---
Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php
RELATED QUESTIONS
How would you find the coordinates of the vertex for the following quadratic function? (answered by midwood_trail)

How would you find the exact coordinates of the vertex for the following quadration... (answered by stanbon)

in the following exercise, find the coordinates of the vertex for the parabola defined by (answered by shree840)

Hi, I'm having trouble with the following question... Find the x- and y-... (answered by solver91311,Theo)

find the coordinates of the vertex... (answered by jim_thompson5910)

find the coordinates of the vertex... (answered by jim_thompson5910,nerdybill)

Change the quadratic function into vertex form. Then, give the coordinates of the vertex. (answered by robertb)

find the coordinates of the vertex y=5x^2-1 (answered by josgarithmetic)

For the parabola 2x^2-4y + 6x + 1 = 0, (a) find the coordinates of the vertex; (b)... (answered by ewatrrr)