SOLUTION: find the value of k that leads to two equal real roots for y=x^2+(k+2)x+2k

SOLUTION: find the value of k that leads to two equal real roots for y=x^2+(k+2)x+2k

Algebra.Com

Question 926356: find the value of k that leads to two equal real roots for y=x^2+(k+2)x+2k
Answer by josgarithmetic(39616) (Show Source): You can put this solution on YOUR website!
Find the expression for the discriminant, and set this discriminant equal to 0.
RELATED QUESTIONS
The equation x^2+(k+2)x+2k=0 has two distinct real roots. Find the possible values of... (answered by ikleyn)

find the range of values of k for which the equation x^2-2kx+k^2-2k=6 has real roots.... (answered by MathLover1)

Given the quadratic equation x^2-15=2k(x-4), find k if there are two real and equal... (answered by stanbon,bucky)

Find the values of k so that the equation {{{(k-2)x^2+4x-2k+1=0}}} has two distinct real... (answered by josgarithmetic)

Find the value of the constant k for which the equation 2x^2+(k+3)x+2k=0 has equal... (answered by ikleyn)

Find the value(s) of k such that the quadratic (k+1)x^2+2kx+2k=3(kx-1) has roots whose... (answered by thesvw)

Solve for the value of k that will make the roots of the function be real and equal:... (answered by josgarithmetic)

Find k so that (k + 1)x^2 + 5x + 2k - 1 = 0 has two real... (answered by MathLover1)

Find k so that the roots of (2k-1)x^2 + (k-1)x - 16 = 0 are numerically equal but... (answered by ikleyn)