SOLUTION: My problem is: An arrow is shot from the top of a 144 foot tower with an initial velocity of 128 feet per second. The height of the arrow, h feet, after t seconds is given by the

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Question 92401: My problem is:
An arrow is shot from the top of a 144 foot tower with an initial velocity of 128 feet per second. The height of the arrow, h feet, after t seconds is given by the equation.
h=-16t^2+128t+144
a. If the arrow reaches its maximum height in 4 seconds, find its maximum height.
b. How many seconds will it take for the arrow to reach the ground?

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
"a. If the arrow reaches its maximum height in 4 seconds, find its maximum height"


Lets find when

Start with the given polynomial


Plug in


Raise 4 to the second power to get 16


Multiply -16 by 16 to get -256


Multiply 128 by 4 to get 512


Now combine like terms


So when ,

So the maximum height is 400 feet




"b. How many seconds will it take for the arrow to reach the ground?"

Let h=0 and solve for t





Let's use the quadratic formula to solve for t:


Starting with the general quadratic



the general solution using the quadratic equation is:



So lets solve ( notice , , and )

Plug in a=-16, b=128, and c=144



Square 128 to get 16384



Multiply to get



Combine like terms in the radicand (everything under the square root)



Simplify the square root (note: If you need help with simplifying the square root, check out this solver)



Multiply 2 and -16 to get -32

So now the expression breaks down into two parts

or

Lets look at the first part:



Add the terms in the numerator
Divide

So one answer is




Now lets look at the second part:



Subtract the terms in the numerator
Divide

So another answer is


So our possible solutions are:
or

However, a negative time doesn't make sense. So our only answer is



So it takes 9 seconds to reach the ground

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