SOLUTION: How do I find the maximum value of Y=x^2-4 when working with quadratic functions

SOLUTION: How do I find the maximum value of Y=x^2-4 when working with quadratic functions

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Question 923584: How do I find the maximum value of Y=x^2-4 when working with quadratic functions
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
How do I find the maximum value of Y=x^2-4
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That doesn't have a max. It has a minimum.
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Find the vertex.
x of the vertex = -b/2a = 0/2
x = 0 --> y = -4
Minimum at (0,-4)
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