SOLUTION: I need some help I am not sure what method was used to solve this problem 4x^2-8x+3=5 4x^2-8x-2=0 2x^2-4x-1=0 x=4+-square root 16-4*2*-1/4 x=4+-square root 24/4 x=4x-2 s

SOLUTION: I need some help I am not sure what method was used to solve this problem 4x^2-8x+3=5 4x^2-8x-2=0 2x^2-4x-1=0 x=4+-square root 16-42-1/4 x=4+-square root 24/4 x=4x-2 s

Question 92105: I need some help
I am not sure what method was used to solve this problem
4x^2-8x+3=5
4x^2-8x-2=0
2x^2-4x-1=0
x=4+-square root 16-4*2*-1/4
x=4+-square root 24/4
x=4x-2 square root 6/4
x=1+1/2square root6 or
x=1-1sqaure root6

Thank you for the help
Found 2 solutions by funmath, stanbon:
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
What method was used to solve this problem?
The quadratic formula was used to solve the problem.
4x^2-8x+3=5
First put the equation in this form:
4x^2-8x-2=0
Then,(and this is optional) they divided every thing by the greatest common factor, 2.
2x^2-4x-1=0
a=2 b=-4 and c=-1
The quadratic formula is:

x=4+-square root 16-4*2*-1/4
x=4+-square root 24/4
Here, I've corrected a slight error:

or
Happy Calculating!!!!

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The quadraatic formula was used.
x=[-b+-sqrt(b^2-4ac)]/(2a)
Cheers,
Stan H.
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