SOLUTION: The graph of a quadratic function f(x) has a vertex at (−1,−4) and passes the point (0,−3). Find the quadratic function. (Note: It is a parabola)
f(x)=
Algebra.Com
Question 919166: The graph of a quadratic function f(x) has a vertex at (−1,−4) and passes the point (0,−3). Find the quadratic function. (Note: It is a parabola)
f(x)=
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
the vertex form of a Parabola opening up(a>0) or down(a<0),
y = a(x+1)^2 - 4
P(0,-3)
-3 = a(1)^2 - 4
1 = a
y = (x+1)^2 - 4
RELATED QUESTIONS
1. Let f(x) = 2x^2 − 8x − 7.
What is the quadratic in vertex form that is y (answered by josgarithmetic)
1. Let f(x) = 2x^2 − 8x − 7.
Write the quadratic in vertex form (that is y... (answered by stanbon)
Let f(x) = 2x^2 − 8x − 7.
Write the quadratic in vertex form
(that is y... (answered by josgarithmetic)
Let f(x) = 2x^2 − 8x − 7.
What is the quadratic in vertex form that is y = (answered by stanbon)
f(x) = −1/2x^2 − 2x + 5
is the function of a quadratic function.
1)... (answered by ewatrrr)
Find the vertex of the graph of the equation.
y = 2x2 − x − 3
Find... (answered by lynnlo)
The graph of a quadratic function f(x) is shown above. It has a vertex at (-2,3) and... (answered by ewatrrr)
Sketch a graph of the quadratic function.
f(x) = x^2 − 2x − 1
Give the... (answered by josgarithmetic)
Find the rule of a quadratic function whose graph has the given vertex and passes through (answered by RAY100)