SOLUTION: The length of a rectangle is 1 cm more than 5 times its width. If the area of the rectangle is 89 cm2, find the dimensions of the rectangle to the nearest thousandth. I don't unde
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Question 91456: The length of a rectangle is 1 cm more than 5 times its width. If the area of the rectangle is 89 cm2, find the dimensions of the rectangle to the nearest thousandth. I don't understand where to even start.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
W=WIDTH
L=LENGTH L=5W+1
AREA=L*W
89=W(5W+1)
89=5W^2+W
5W^2+W-89=0
USING THE QUADRATIC EQUATION:
WE GET
W=(-1+-SQRT[1^2-4*5*-89])/2*5
W=(-1+-SQRT[1+1780])/10
W=(-1+-SQRT1781)/10
W=(-1+-42.2)/10
W=(-1+42.2)/10
W=41.2/10
W=4.12 ANSWER FOR THE WIDTH
L=5*4.12+1
L=20.6+1
L=21.6
PROOF
4.12*21.6=89
89=89
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