SOLUTION: h(x)=2x^2+6x+25 Find the vertex and axis of symmetry.

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Question 913239: h(x)=2x^2+6x+25
Find the vertex and axis of symmetry.

Found 2 solutions by ewatrrr, Fombitz:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
h(x)=2x^2+6x+25
h(x)=2(x + 3/2)^2 - 9/2 + 25
h(x)=2(x + 3/2)^2 + 41/2
V(-3/2, 20.5)
axis of symmetry: x = -3/2


Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
Convert to vertex form,





The vertex is (,).
The axis of symmetry is
The parabola opens upwards.


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