SOLUTION: ax^2+(a+1)x+(a-1) = 0 I need to solve this equation for x. I've been trying to factor it to no avail... Honestly I don't even know where to start. I tried factoring out an x, on

Question 912647: ax^2+(a+1)x+(a-1) = 0
I need to solve this equation for x. I've been trying to factor it to no avail... Honestly I don't even know where to start. I tried factoring out an x, only to realize that there is no x in the last term. I'm so stuck, please help!
Found 2 solutions by richard1234, josgarithmetic:
Answer by richard1234(7193) (Show Source): You can put this solution on YOUR website!
Use the quadratic formula, replacing "b" with "a+1" and "c" with "a-1" and the problem is solved.
Answer by josgarithmetic(39616) (Show Source): You can put this solution on YOUR website!
Any reason you must FACTOR?

An attempt:
ax^2+ax+x+a-1=0
ax^2+ax+a+x-1=0
a(x^2+x+1)+x-1=0

General Solution for Quadratic Equation.
...

This does not seem to be simplifiable any further.
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